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Tentukan titik yang paling atas pada fungsi kuadrat y=-x²+x, y=-x²-x

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  • Tentukan titik yang paling atas pada fungsi kuadrat y=-x²+x, y=-x²-x

    Tolong bantu!!

  • #2
    y = -x2 + x:
    a = -1, b = 1, c = 0
    x = -b/2a = -1/2(-1) = 1/2
    y = -x2 + x = -(1/2)2 + 1/2 = -1/4 + 1/2 = -1/2
    Titik yang paling atas: (1/2, -1/2)

    y = -x2 - x:
    a = -1, b = -1, c = 0
    x = -b/2a = -(-1)/2(-1) = -1/2
    y = -x2 + x = -(-1/2)2 + 1/2 = -1/4 - 1/2 = -3/2
    Titik yang paling atas: (-1/2, -3/4)

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